Viewed 43k times 0 I want to. date_open are both of type date, you can simply subtract them to get a difference in days. Parameter Description; interval: Required. 2903225806. Oracle Database enables you to perform arithmetic operations on dates and time stamps in several ways: Add a numeric value to or subtract it from a date, as in SYSDATE + 7; Oracle Database treats the number as the number of days. Asked 2 years, 9 months ago. Now for testing purposes I need to compare the data for the last say 4 months from the sysdate. SQL DATEPART. S is milliseconds in one or up. You can't transform this value to date by to_date function. How can I calculate the date difference between these 2 columns? sql; sql-server-2008; t-sql; datediff. So it's not an accumulative difference, it's only when a date is within a smaller month. Tip 032: Summary of Date Functions. Month difference between two dates in sql server. This is from my own library, will return the difference of months between two dates. Otherwise, the resulting date has the same day component as. The integer value represents the day and the fractional value represents the. event_id, evnt. TotalDays([EndDate]-[StartDate])/30 . It counts the number of year boundaries between two dates. for the month differnce the standard sql is DATEDIFF, in this function you must pass 3 params, if you must calculate the difference from 2 columns, c1 and c2, you must do this query SELECT DATEDIFF(month,c1 , c2) FROM T WHERE. DATEDIFF(expr1,expr2) DATEDIFF() は、ある日付から別の日付までの日数の値として表現された expr1 − expr2 を返します。expr1 および expr2 は、日付または日付時間式です。 値の日付部分のみが計算に使用されます。One practical example of using the DATEDIFF function in SQL Server is in a WHERE clause by selecting all employees in the AdventureWorks2008R2 database whose date of hire was in March 2003. The int data type takes 4 bytes as storage size whereas. All functions can be used in both the load script and in chart expressions. I need to get the numbers of the months between two dates. To get the start and end dates of each month within a given range, when the value of the @StartDate parameter is not the first day of the month: The first option is to truncate the @StartDate parameter to the. But I suggest you add a computed column to the table: alter table Family add AgeYears as Year (getdate ()) - Year (dob) - 1 + case when Month (getdate ()) > month (dob) then 1 when month (getdate ()) < month (dob) then 0 else case when day (getdate ()) >= day (dob) then 1 else 0 end end. The unit of time. The DATEADD() function adds or subtracts a specified time interval from a date. Snowflake doesn't offer a function that does that. Taking out our calculator, we see that 30 minutes equals 1day/24hours*0. StartDate) AND. create table test_table ( customer_num NUMBER, card_number char(2), card_issue_date DATE, card_expire_date DATE ). Unfortunately, Oracle SQL doesn't allow the DATEDIFF function. 8494441'. DECLARE @ADate DATETIME SET @ADate = GETDATE () SELECT DAY (EOMONTH (@ADate)) AS DaysInMonth. datediff (q,start date,end date) i. g. Now it only runs DateAdd () once, and it can use an index (if one exists), to only load the rows that match the predicate criterion. 25)) AS `numberofemployees`. ss is two digits of second (00 through 59). mysql> SELECT something FROM tbl_name-> WHERE DATE_SUB(CURDATE(),INTERVAL 30 DAY) <= date_col; The query also selects rows with dates that lie in the future. Here's how it does this: First the DATE function creates the date, 5/1/2016. SQL - two months from todays date in Oracle. The datediff function returns the difference between two specified dates in the time units that you specify: years, quarters, months, weeks, days, hours, minutes, or seconds. The return type is always DATE, regardless of the datatype of date. 000 which is the start of the. SELECT TIMESTAMPDIFF (MONTH, '2012-05-05', '2012-06-04') -- Outputs. 1 Answer. COMPUTE days2 = DATEDIFF(date2,date1,"days"). See the following conditions: If date1 is later than date2, then the result is positive. In this article, we learned how to do SQL subtract dates using the DATEDIFF function. DateDiff ( date1, date2, date_part) パラメータ 説明; date1. 1,984 1 1 gold badge 17 17 silver badges 31 31 bronze badges. 構文 @DATEDIFF (' difference ', ' date ', ' date ') difference. After executing the above query, we got the following output: SHOW_DAY. Would give you rows where date2 (the later date) is 60 to 90 days later than date1. If you are familiar with Microsoft SQL Server functions but are new to Oracle databases, see Character Functions to compare SQL functions support in Microsoft SQL. Both integer (int) and big integer (bigint) are numeric data types used to store integer values. g. In addition, with DATEDIFF () the column is an argument to the function. Date, DateTime, and Time Out Wrappers for SQL and Dynamic Views. Try SELECT SYSTIMESTAMP + INTERVAL '5' MINUTE, SYSTIMESTAMP + 5 / 24 / 60 to convince yourself. Calculate difference between 2 date / times in Oracle SQL. See Date and Time Data Types and Functions (Transact-SQL) for an overview of all Transact. DateDiff function and I think it may have a parameter for indicating "in months" . The Oracle NEXT_DAY() function returns the date of the first weekday specified by day name that is later than a date. Weeks. select (dt1-dt2) * 24 * 60 * 60 from t; dt1-dt2 gives diff in days (eg: 1. 7 Reference Manual :: 12. v_weekenddays := floor (v_interval / 7) * 2; -- calculate aproximate number of weekend days between the two dates. Oracle SQL time difference in HH:MM:SS. Date manipulation is a common scenario when retrieving or storing data in a Microsoft SQL Server database. This works because you have no issue with months and years or one-digit vs. (year/month/date from date) //oracle function for extracting values from date. date_from, evnt. SELECT * FROM TABLE_NAME WHERE DATEADD (DAY, -90, GETDATE ()) between txtFromDate and txtToDate. In SQL Server, there is a function datediff with datepart 'q'/quarter which behaves as follows :--. Modified 1 year, 8 months ago. Dynamic views containing Date, Time, or DateTime fields must be wrapped with the appropriate meta-SQL. (Oct 10, 2006 - June 14, 2005 = 69) SELECT months_between ( date_1, date_2 )/12 years_between FROM employee. Its seems that "DATEADD ": invalid identifier. In certain cases, such as string-based comparisons or when a result depends on a different timestamp format than is set in the session parameters, we recommend explicitly converting. SQL> ed Wrote file afiedt. In most use cases, Snowflake correctly handles date and timestamp values formatted as strings. For example, the function considers each of the following pairs of dates/timestamps to be exactly 1. Just out of curiosity, have you paid the $95 for a manual yet? ;-) If not, get the thicker one when you do unless you are pretty familiar with the commands and just need a reference. 0 months apart:Let’s see a few examples of SQL subtract date from the DATEADD function: In the below example, we are adding one month to the existing date ‘20220730’. Functions, you can call DateDiffDay: var ans = from t in Table1 group t by 1 into tg select tg. 58064516129032. Property)) STDEV(Property) EF Core 7. If date1 is earlier than date2, then the result is negative. The difference between 1st March 2011 and 29th February 2012 is 0. So, this expression converts SYSDATE to a string, using whatever local settings are on your system. NEW_TIME returns the date and time in time zone timezone2 when date and time in time zone timezone1 are date. DATE_ADD () Add time values (intervals) to a date value. ArrivalDate, Trips. This function helps to retrieve any particular value of the timestamp in any format that we wish. So if the timeframe is longer than a working week (five days) you can: Find the number of weeks by taking the floor of the N / 5. For formatting functions, refer to Section 9. Was this tutorial helpful? Previously Oracle ROW_NUMBER Up Next Oracle ADD_MONTHS This tutorial provides you with the most commonly used Oracle date. In PostgreSQL, you can take the difference in years, multiply by 12 and add. So, Feb-28 to Mar-28 is a month. current_timestamp() returns the timestamp on the database client side. Improve this answer. 3 Answers. The math is 100% accurate for dates within a couple of hundred years or so. 0: EF. You can use this methodology to determine the first day of 3 months ago, and the last day of the previous month: select DATEADD (MONTH, DATEDIFF (MONTH, 0, GETDATE ())-3, 0) --First day of 3 months ago select DATEADD (MONTH, DATEDIFF (MONTH, -1, GETDATE ())-1, -1) --Last Day of previous month. from this previous question How to calculate age in T-SQL with years, months, and days you can do procedure like this. SS: 差異を秒数で計算します。. The age in days between the two dates is either 2 or 3 days, but in one case the DATEDIFF function returns an Int data type. 5 = 0. 6. From the documentation: date_part (): The date_part function is modeled on the traditional Ingres equivalent to the SQL-standard function extract:Date/time functions. Functions. 8. Aug 17, 2021 at 11:13. The datediff function returns the difference between two specified dates in the time units that you specify: years, quarters, months, weeks, days, hours, minutes, or seconds. Add a comment. 1. DateGroup. 1 - Find the total months count till today's date using DATEDIFF function -. What's the function in Oracle that would be the equivalent to DATEDIFF in the SQL Server? On Oracle, it is an arithmetic issue: Select DATE1. So I am porting many SQL Procedures to Oracle. For example, we can use the DATEPART function to get the day of a given date to determine whether an order was placed on Sunday or not. Transact-SQL. i. To create the rows, use the month generation technique above. So if there are two dates separated by one day, the year difference can be 1 (see select datediff (year, '20141231', '20150101') ). You get the difference in days. How to use system date & formulas based on system date as Part of prompts in OTBI reports? The goal is to create a couple of prompts, based on the range of, 5 days prior to current system date and current. Only 10+ years later - here's a db<>fiddle which demonstrates the difference between subtracting a date from a date (e. Usage Notes¶. DATE () Extract the date part of a date or datetime expression. See the following conditions: If date1 is later than date2, then the result is positive. Sorted by: 55. Share. *Subtract the two date values, divide by (60 seconds * 60 minutes *. The solution takes as base the first known date by SQL Server (1900-01-01). Description. ROUND(p1) ROUND(p1, p2) Not Available. This function adds N months to a date and returns the same day N month after. 0208 days. ) and rest are two dates which you want to compare. SELECT DATEADD (month, 1, '20220730'); The below DATEADD will add 1 year to the provided date value, the year changed from 2022 to 2023. 1 row created. Admission_Date < ADD_MONTHS (sysdate, -5) which could still use an index on that column, if there is one. January 1 of any year defines the starting number for the week datepart, for example: DATEPART (wk, 'Jan 1, xxxx') = 1, where xxxx is any year. date_open END. sql. SELECT DATEDIFF (month,'2011-03-07' , '2021-06-24'); In this above example, you can find the number of months between the date of starting and ending. DateDiff(“m”, Fields! starting date. This is not permitted when the subquery follows =, !=, <, <= , >, >= or when the. I want to select some data from one table if a date from another table is at least 6 months before today. txt","path":"inst/csv/jarChecksum. 0. startdate, DATEDIFF(DAY,e1. The expression is given to calculate the month’s difference between two dates, use the date diff expression as shown below. For example, you can use this function to find the date that is 7000 minutes from today: number = 7000, datepart = minute, date = today. Another solution by using Cross Apply:. mysql> SELECT EXTRACT (DAY FROM "2021-10-24") AS SHOW_DAY; Here, we have written a SELECT query with the EXTRACT () function to get the day from the given date. 2323 days) multiply by 24 = hours, another 60 = minutes, another 60 = seconds. Syntax. last_day (feb) to last_day (mar) is also commonly accepted as a "month". Modified 3 months ago. DATEDIFF(MONTH, 0, GETDATE())-1, 0) AND DATEADD(MONTH, DATEDIFF(MONTH, -1, GETDATE())-1, -1) based on the comment below I have modified the query. CREATE procedure [dbo]. SQL> select 24 * (to_date ('2009-07-07 22:00', 'YYYY-MM-DD hh24:mi') - to_date ('2009-07-07 19:30', 'YYYY-MM-DD hh24:mi')) diff_hours from dual; DIFF_HOURS ---------- 2. Purpose MONTHS_BETWEEN returns number of months between dates date1 and date2. PostgreSQL. I apologize for the misinformation. 2323 days) multiply by 24 = hours, another 60 = minutes, another 60 = seconds. DATEDIFF_BIG () is a SQL function that was introduced in SQL Server 2016. YEAR: Stores the year information only, either in 2-digit or 4-digit format. It can be used to do date math as well. Try SELECT SYSTIMESTAMP + INTERVAL '5' MINUTE, SYSTIMESTAMP + 5 / 24 / 60 to convince yourself. SELECT TIMESTAMP_FORMAT (“2021-03-15”, “%Y”) as “Year of the date”; TO_DATE. ArrivalDate, Trips. It should be 24 months. SELECT DATEADD (month, 1, '20220730'); The below DATEADD will add 1 year to the provided date value, the year changed from 2022 to 2023. Summary: in this tutorial, you will learn how to use the SQL DATEPART () function to return a specified part of a date such year, month, and day from a given date. i need to find the difference of two dates as the number of months: find the last day of the month of both the dates. Oracle has a months_between function: AND MONTHS_BETWEEN (sysdate, s. Share. Sorted by: 3. measure is the name of a measure column. For ADD_MONTHS only, if the original day is the last day of the month, the. I was given code via an SR but it doesn't work (I'm able to save the code but when I try to look at the sample data, it just says "error"). 24 th is the day value in the given date. datepart: It is the part of the date like day, month, year, week, etc. So in order to get specific type of delivery for the last 3 months I was thinking to get today's date and convert it to 01/mm/yyyy format and ref it with the delivery month in the table to get least 3 month including. It returns a whole month (no fraction) if both dates have the same day-of-month or both are the last day of the month. Then it would also be helpful to be able to. Thanks for the infoFirst step is to join the tables together such that we get a row for every relevant month that intersects with the start and end dates in your HRAL table. I need to calculate the difference between two dates in Oracle sql and show it in the following format: 'x years y months z days'. Then you'll see the number. For example: print &order_date () edit 'Month dd, YYYY'. g. Calculate the last date of the month is quite simple calculation -. Also, according to Oracle's documentation LAST_DAY returns a DATE. Given two dates then the difference between them is a number of full calendar months and the remainder is the number of days (and hours, minutes and seconds) - this is easy to find using the MONTHS_BETWEEN function and some modulo arithmetic (see my. %DateDiff – returns the number of days between two date values. g. FROM_DAYS(): This function finds the date from the specified numeric date value. E. Expressions must contain a complete hint. Assuming that a. 99. 1. TIMESTAMP or TIMESTAMPZ. Arguments. If you want to confirm, simply run this. 24. Here is some T-SQL that gives you the number of years, months, and days since the day specified in @date. Not all of the expressions described at the URL are supported in NetSuite. Return the current time. The table contains the data about each staff member’s employment date. I am trying to create a new column that will show the age of the person on the date that they took up the membership. In Oracle SQL, I want to display the difference between two dates in the format 'x years y months z days'. Just divide the total by 7 to get the weeks and then calculate the remaining days. Field or Control. The next example will show the differences between two dates for each specific datapart and abbreviation. The default is date format 1. Oracle equivalent to SQL Server/Sybase DateDiff. Example Getting the months and years between two dates using Datediff There is a round up issue with the Datediff function. We learned with examples, how to get information. The second row is only 30 minutes apart, so the difference is 0. 2903225806. Run SQL ». select months_between(date '2015-03-19', date '2012-01-06') as month_diff from dual; MONTH_DIFF ----- 38. DECLARE @date datetime2 = '2021-01-07 14:36:17. from a date time value. Currently, my code just returns zero on the right side of the decimal place. Syntax:DATEDIFF Examples Using All Options. members, Datediff( GetFirstDate([Time dimension]. The DATEDIFF() function returns the number of days between two date values. then just use it in the script eg. sql. SELECT DATEDIFF (second, '2019-12-31 23:59:59', '2020-01-01 00:00:00'); A value of 1 is returned because the boundary of seconds is crossed once. If year numbers are different calculation of 52 * year difference + week number. columns c puts a limit on how many dates are returned. Subtracting two dates will return if and only if they are the same year, the same month, the same day, the same hour, the same minute, and the same second. v_modweek := mod ( v_interval, 7); -- calculate how many days remain after computing the total number of. I am looking for solution how to select number of days between two dates without weekends and public holidays. If within the same year, you can use Date. There are several date functions (DATENAME, DATEPART, DATEADD, DATEDIFF, etc. Hi tom, I want day, month, minute and years difference everyting in seconds. I guess I did not read the question in depth. DateAdd. Our SQL tutorial will teach you how to use SQL in: MySQL, SQL Server, MS Access, Oracle, Sybase, Informix, Postgres, and other database systems. When the reporting date month is the same as the target month you can get a round up To get the number of month or day, you change the first argument to month or day as shown below: Notice that the DATEDIFF () function takes the leap year into account. Improve this answer. But your query is giving the last date of previous month. Kindly tell me how to calculate age as in years month days. Viewed 110k times 49 I have a table with following structure. Here is an example that uses date functions. enddate,e3. current_time() returns the date and time on the database client side. Accountnumber = T1. date_from) = 1. The value can be a string literal or can be unquoted (e. This function adds a specified number of days, months, and years to a given date. I tried going off of something like this: Select records from SQL Server if greater than 6 months but I get the error: Subquery returned more than 1 value. Sure, the query depends on which database you’re using (Oracle, SQL Server, MySQL, etc). hh is a two digits of hour (00 through 23). Function. 997268 (0 year + 365/366 years) So, in summary, the output (in DECIMAL (7,6)) from the above two examples would be: 1. , year, quarter, month, day, hour, minute, second), startdate is the starting date or time, and enddate is the ending date or time. SHOW_DAY is an alias to store the day. datediff() is not giving tHe result as I am working in Oracle. 1. 2258064516 DATE_DIFF = 1. 0. this will be add to 1900-01-01 , but only the months. If you enter a negative parameter, the system subtracts the specified days, months, or years. Here is the synopsis: If using Oracle use the trunc and numtoyminterval functions; if using SQL Server use the datediff function. The expression is given to calculate the month’s difference between two dates, use the date diff expression as shown below. Dte <= @gapPeriod; --only older records. In SQL Server 2012 you can use EOMONTH (Transact-SQL) to get the last day of the month and then you can use DAY (Transact-SQL) to get the number of days in the month. (You can also subtract fractions of days, but that might be outside the scope of this answer. Now I see two ways to achieve this: The MONTHS_BETWEEN () function is used to get the number of months between dates (date1, date2). I used the following code: SELECT h. I have a definition query defined on a feature class coming from an Oracle SDE where a date field is queried to return values within 6 months of the current date (see below) RELDATE_DATE > ADD_MONTHS (TO_DATE (SYSDATE),-6. Share. 10. DATEDIFF is a common function in the SQL Server to find the number of days between two dates. date_from, evnt. CREATE OR REPLACE FUNCTION datediff (p_what IN VARCHAR2, p_d1 IN DATE, p_d2 IN DATE) RETURN NUMBER /* Updated to reflect current database and PL/SQL. So, there’s. For Oracle: Last 6 Months. These functions assist in comparing, adding, subtracting, and getting the current date and time, respectively. StandardDeviationPopulation(group. Difference of two dates in months. MONTHS_BETWEEN (TO_DATE ('2003/01/01', 'yyyy/mm/dd'), TO_DATE ('2003/03/14', 'yyyy/mm/dd') ) would return -2. You may have to re-cast to a DATE datatype first. I want to calculate the current Age from Date of Birth in my Oracle function. Add a. This post has been answered by 630199 on Jun 1 2009. Dateadd function is not working in oracle SQL. We need to subtract a second from first day of current month. Which leads me to believe that it is treating February. , SYSDATE - pr. What I am using is (Today-Dob)/30/12, but this is not accurate as some months have 31 days. SELECT DATE '0016-08-03' - DATE '2016-07-08' FROM dual;-- -730461. date_to) - (DATEDIFF(WK, evnt. T was trying do calculate age as on todays date in ORACLE but after a lot of brain storming i didn't get it. SELECT SYSDATE AS "Date" FROM DUAL; SYSDATE returns the system date and time but does not display the time unless formatted to do so with the function TO_CHAR (): SELECT TO_CHAR (SYSDATE,. object_id ) AS nbr FROM sys. If you really want 'datediff' in your database, you can just do something like this: Now, i just create a view to demonstrate with: SQL> select datediff ( 'ss', d1, d2 ) seconds from temp_view; SECONDS6269539. The recommended solution on Stack Overflow for example is this. CurrentMember), Today(), DP_MONTH ) < 6 ) ON ROWS FROM Mysamp. DATEDIFF(date1, date2) Parameter Values. End Function. 2. (You can also subtract fractions of days, but that might be outside the scope of this answer. As such, the use, reproduction, duplication, release, display, disclosure, modification, preparation of derivative works, and/or adaptation of i) Oracle programs (including any operating system, integrated software, any programs embedded, installed, or activated on delivered hardware, and modifications of such programs), ii) Oracle computer. – WAMLeslie. It operates according to the rules of the Gregorian calendar. The schema is SYSIBM. For example, suppose you have values below the start and end times. 7 months ago. Share. (Oct 10, 2006 - June 14, 2005 = 69)SELECT months_between ( date_1, date_2 )/12 years_between FROM employee. Follow edited Apr 7, 2020 at. MySQL :: MySQL 5. Tip. SELECT floor ( months_between ( date_1, date_2 )/12) floor_years_between FROM employee. Start date will be equal to add_months(sysdate,-6) And . INTERVAL '15. DATEADD (date part, units, date or datetime) Return date math results: datetime DATEDIFF (date part, start date, end date) Give the difference between 2 dates in units specified by. Oracle equivalent to SQL Server/Sybase. 4193548 The number of whole months can be split into. The days are in two different, adjacent months, so the answer is 1 month difference. If you are using MySQL there is the DATEDIFF function which calculate the days between two dates: SELECT dtCreated , bActive , dtLastPaymentAttempt , dtLastUpdated , dtLastVisit , DATEDIFF (dtLastUpdated, dtCreated) as Difference FROM Customers WHERE (bActive = 'true') AND (dtLastUpdated > CONVERT (DATETIME,. If you need to get last day with. Discussion: To calculate the difference between the timestamps in Oracle, simply subtract the start timestamp from the end timestamp (here: arrival - departure ). Each Standard calendar week is defined to start on Sunday and it spans 7 days. Interprets an INT64 expression as the number of days since 1970-01-01. oracle; datediff; or ask your own question. 14. Instead of: datediff ('QUARTER', pr. 33 shows the available functions for date/time value processing, with details appearing in the following subsections. 7 Date and Time Functions. 6222691' DECLARE @date2 datetime2 = '2022-01-14 12:32:07. I recommend you have a stab yourself. for example Feb-15th to Mar-15th is a month. The result only contains the year, month and day, not the time. Share. substr (to_char (to_date ('01-02-2018','mm-dd-yyyy'), <NLS_DATE_FORMAT>),4,3) The usual default value (for English-language versions of. Once you have the date difference, you can use simple techniques to express the difference in days, hours, minutes or seconds. If you also need the additional months old, and days old. Modified 7 years, 2 months ago. January 30, 2004 - 7:26 pm UTC. Improve this answer. E. 首先在oracle中没有datediff ()函数. It operates according to the rules of the Gregorian calendar. Take these examples: Example 1 Date 1: 10th March 2011 Date 2: 3rd Feb 2011 MONTHS_BETWEEN = 1. Date2Date. 2425): datediff (day, {start-date}, {end-date},) / 365. 0. Also I am not sure about Oracle, mysql,. They both do very different things. We would like to show you a description here but the site won’t allow us. We would like to show you a description here but the site won’t allow us. DATEDIFF does not guarantee that the full number of the specified time units passed between 2 datetime values: -- Get difference in hours between 8:55 and 11:00 SELECT DATEDIFF (hh, '08:55', '11:00'); -- Returns 3 although only 2 hours and 5 minutes passed between times -- Get difference in months between Sep 30, 2011 and Nov 02, 2011. If date1 is earlier than date2 , then the result is negative. This gets the year difference between the birth date and the current date. The month and the last day of the month are defined by the parameter NLS_CALENDAR. I want to calculate the current Age from Date of Birth in my Oracle function. I want to find out the customers who have made orders on three successive months. e it takes the quarter in which the start date exists and subtracts it from the quarter in which the end date exists. When you subtract two dates in Oracle, you get the number of days between the two values. Oracle equivalent to SQL Server/Sybase DateDiff. (Query using SQL server 2005 and 2008 is allowed). DATE_FORMAT(): This function formats a specified date as per the format specifier (%e for date, %c for month, %Y for year, and many more). So, the difference between Jan 1 20015 and Dec 31 2016 is 1 year. select add_months ( date'2021-01-01', ( level - 1 ) * 12 ) as yr_add_months, date'2021-01-01' + numtoyminterval ( level - 1, 'year' ) yr_interval from dual connect by. Connect and share knowledge within a single location that is structured and easy to search. Example 2. ss is two digits of second (00 through 59). 1. How To turn a string with "pipe-separated" values into individual rows in Oracle PL/SQL. 1. DATEADD(month, DATEDIFF(month, 0, getdate())+1, 0) returns the beginning of next month. Syntax. Converting a raw number of days into a number of weeks and days is pretty simple. As shown clearly in the result, because 2016 is the leap year, the difference in days between two dates is 2×365 + 366 = 1096. Thanks in advance for any help; this has been driving us crazy for a few months now. We’re calculating months of service in this example. Select DATEDIFF (MM,0,GETDATE ()) Output - 1374, If getdate () output is "2014-07-23 19:33:46.